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Factor expressions

Factor a quadratic like x² + 5x + 6 quickly

Random trial-and-error for the two numbers wastes time; a sum-and-product search is systematic.

Spot it when

You need to factor x² + bx + c (or split the middle term of ax² + bx + c).

e.g.x2+5x+6x^2 + 5x + 6

Watch it solved

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Factor the trinomial

Vyaṣṭisamaṣṭhi balances the "individual" (the parts) with the "whole." For x² + bx + c, we need two parts that fit both the product and the sum.

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Factor the trinomial

Vyaṣṭisamaṣṭhi balances the "individual" (the parts) with the "whole." For x² + bx + c, we need two parts that fit both the product and the sum.

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⚡ Speed Advantage

Vedic
5 steps
Traditional
6 steps

See how few steps Vedic method needs!

When you’ll actually hit this

Real moments — exams, homework, competitions — where this shortcut earns its keep.

Homework

A garden of area x² + 5x + 6 needs its two side lengths for the next part of the question.

becomesfactor x2+5x+6x^2 + 5x + 6

Two numbers with product 6 and sum 5 are 2 and 3 → (x+2)(x+3).

Exam crunch

A non-monic quadratic 6x² + 5x − 6 appears and you need its factors fast.

becomesfactor 6x2+5x66x^2 + 5x - 6

Split the middle term using the sum/product targets → (2x+3)(3x−2).

In class

A sign-trap quadratic in class: product negative, sum positive.

becomesfactor x2+4x21x^2 + 4x - 21

Product −21, sum 4 → 7 and −3 → (x+7)(x−3).

The method behind it

व्यष्टिसमष्टि

Vyaṣṭisamaṣṭhi

Part and whole

Factor a quadratic by finding two numbers whose sum is the middle coefficient and product is the last — the Vedic way to factor trinomials.

Conventional

trial and error factoring — variable steps.

Vedic

systematic sum-and-product recognition.

Structured search replaces random trial-and-error.

Use when

  • Quadratic trinomials, factorization problems

Avoid when

  • Irreducible polynomials over integers

Master it