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यावदूनम्

Yāvadūnaṃ

"Whatever the deficiency"

What this sutra solves

Square a number that sits near 100 or 1000 with almost no arithmetic.

A square tile is 98 mm on each side and you need its area.

becomes98298^2

Deficiency −2: 96 | 04 → 9604 sq mm.

A 103 m × 103 m field — area?

becomes1032103^2

Surplus +3: 106 | 09 → 10609 sq m.

Live Demo
Working Base
100
number
98
-2
deficiency
1

Choose the base

98 is near 100. deficiency 2.

1 / 5

⚡ Speed Advantage

Vedic
2 steps
Traditional
8 steps

4× faster with Vedic Mathematics

Best for

  • Squaring numbers near powers of 10

Use when

  • Squaring a number close to 10, 100, 1000, etc.

Avoid when

  • Numbers ending in 5 (use Ekadhikena), numbers far from base

Intuition

Square a number near a base: subtract (or add) the deficiency to get the left part, square the deficiency for the right part.

Story Mode

The Deficit Squared

How far are you from 100? That distance — your deficiency — is the key. Reduce the number by that same deficiency for the left, square the deficiency for the right. The base 100 acts like a scaffold that the final answer hangs from.

Vedic vs conventional

Conventional: 982=98×9898^2 = 98\times 98 via long multiplication. Yaavadunam: deficiency 2, left=982=9698-2=96, right=22=0496042^2=04 \to 9604 (2 steps).

2 mental steps vs 8+ for squaring numbers near a base.

Applications

Squaring numbers near a base

Any number within ~15% of a power of 10 squares in 2 steps.

98298^21032103^29972997^210004210004^2

Common Mistakes to Avoid

Padding the right part to match base digit count

Wrong approach

19972997^2: deficiency 3, right=32=93^2=9
must write '009' for base 1000

Correct approach

Right part must have exactly as many digits as zeros in the base.

Why this happens

💡 Same error as Nikhilam — forgetting to pad.

Why It Works

Let the number be below the base:

n=Bdn=B-d

Square it:

n2=(Bd)2=B22Bd+d2n^2=(B-d)^2=B^2-2Bd+d^2

Factor by the base:

=B(B2d)+d2=B(nd)+d2=B(B-2d)+d^2=B(n-d)+d^2

The left part is n minus the deficiency; the right part is the square of the deficiency, padded to the base width.

For n near base B with deficiency d (n=Bdn = B-d): n2=(Bd)n^2 = (B-d)² = B22Bd+d2=BB^2-2Bd+d^2 = B(B2dB-2d)+d2=Bd^2 = B(ndn-d)+d². Left part = nd=B2dn-d = B-2d; right part = d². Above base: n=B+dn2=Bn = B+d \to n^2 = B(n+dn+d)+d².

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